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Old 08-15-2011, 06:24 AM   #1
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Equation on the relationship between extension


(n one-element equation in: lVal = b, ..., Va = b has at least one established, single-equation and a dollar inequality solution, respectively by (6) and (10) is given, we introduce the notation: Z (beal, bea2, ... bea), Z Jin (beal, bea2, ... bea), its specific meaning and the meaning and Y is similar. No. 2 Jiang Jinsong: On the relationship between the equation of extension to make 'is the first i would Z. a component into the i-th component of Z obtained by the vector,-w () = (6ea1 ... 6ea ... beZ-a), then (12) the solution set is:''U''U ... himself, ' namely: z = ('or-w (2' or ... or (a) If the solution can expand equation: (z1A6) V (x2A4) V (z5A5) V (4A8) = 7731, bca +1, then: Y = (786,784,785,788 )=(,,, 7) Y = (786,784,785,788 = ((a o., + o.), (a o., + o.), (a o., + o ,Beats By Dre Headphones。),(~ o.,tods shoes outlet, 7)) is: W''=,MBTシューズ 販売店, W''=, W''=,vibram five fingers outlet, W ()=(( a ∞, + ∞), (a ∞, + oo), (a o., + ∞), 7) w [4) is the demand of the solution, the solution set of the solution has infinitely many now consider, z-element extension of linear equations (4 ), because the solution set of equations is equal to the equation set to pay: remember kind of matrix from the Y Y R = 618a11b1 & 21 ... b1 as 16212bz8azz ... 628a268a1bm8a2 ... 6 as much as blba11621261 Sun 21622261 Sun 16226 Sun, 2 ... 6 of 16 each line were selected on behalf of a non-empty element of many people replace the corresponding position in the Central Plains and some elements to get a matrix W, that W Total: R1 + R2 + ... + R a,herve leger toronto, where R is Y i in the intersection co- operations, the resulting row vector is a part of the solution set of linear equations if the extension: remember: Z △ ble. 11b2e. 12b1Ca21b2Ca22 African air lines the number of elements of each matrix w, for each column set , all part of the solution set of requirements and would be the total solution set. (al1Vx1) A (. 21Vx2) A ... A ((a12Vx1) A (. 22Vx2) A ... A (● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● (a1Vx1) A (a2mVx2) A ... A (b1ea month 1b2ea26e. 1mbm ~ a2 Ⅲ ... 6 Ⅲ En month m (4) Similarly we can get (13) the solution collection, full mouth 1Vx) port 2Vx) b162anmVx) = bb1e. 11bl ~ a21 ... b1ea More articles related to topics:


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